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led.vhd
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----led
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
USE IEEE.numeric_std.ALL;
ENTITY led IS
PORT (
clk : IN STD_LOGIC;
num1 : IN STD_LOGIC_VECTOR(3 DOWNTO 0) := "0000";
num2 : IN STD_LOGIC_VECTOR(3 DOWNTO 0) := "0000";
num3 : IN STD_LOGIC_VECTOR(3 DOWNTO 0) := "0000";
num4 : IN STD_LOGIC_VECTOR(3 DOWNTO 0) := "0000";
seg : OUT STD_LOGIC_VECTOR(6 DOWNTO 0);
dig : OUT STD_LOGIC_VECTOR(4 DOWNTO 1)
);
END ENTITY led;
ARCHITECTURE rtl OF led IS
COMPONENT hex_to_7_seg
PORT (
seven_seg : OUT STD_LOGIC_VECTOR(6 DOWNTO 0);
hex : IN STD_LOGIC_VECTOR(3 DOWNTO 0));
END COMPONENT;
SIGNAL myclk : STD_LOGIC := '0';
SIGNAL cnt : INTEGER := 0;
SIGNAL id : INTEGER RANGE 1 TO 4 := 1;
SIGNAL out1, out2, out3, out4 : STD_LOGIC_VECTOR(6 DOWNTO 0);
BEGIN
U1 : hex_to_7_seg PORT MAP(out1, num1);
U2 : hex_to_7_seg PORT MAP(out2, num2);
U3 : hex_to_7_seg PORT MAP(out3, num3);
U4 : hex_to_7_seg PORT MAP(out4, num4);
PROCESS (clk)
BEGIN
IF rising_edge(clk) THEN
cnt <= cnt + 1;
IF cnt >= 5e4 THEN
myclk <= NOT myclk; --创造一个1Khz的时钟 = 1ms
cnt <= 0;
END IF;
END IF;
END PROCESS;
PROCESS (myclk)
BEGIN
IF rising_edge(myclk) THEN --1ms LED刷新一个数,就是只亮一个数字,其余三个数字都不亮.
dig <= "1111";
dig(id) <= '0';
CASE id IS --这四个数循环的亮,因为视觉暂留
WHEN 1 =>
seg <= out1;
WHEN 2 =>
seg <= out2;
WHEN 3 =>
seg <= out3;
WHEN 4 =>
seg <= out4;
END CASE;
id <= id + 1;
IF id > 4 THEN
id <= 1;
END IF;
END IF;
END PROCESS;
END ARCHITECTURE rtl;