</> Aggressive Cows ! Well this helps! (Python(3.10))

[anudeepkantamaneni]

def aggressiveCows(stalls: list[int], k: int) -> int:
stalls.sort()
low = 1
high = stalls[-1] - stalls[0]
result = 0

def can_place_cows(distance: int) -> bool:
    count = 1
    last_pos = stalls[0]
    for i in range(1, len(stalls)):
        if stalls[i] - last_pos >= distance:
            count += 1
            last_pos = stalls[i]
            if count == k:
                return True
    return False

while low <= high:
    mid = (low + high) // 2
    if can_place_cows(mid):
        result = mid
        low = mid + 1
    else:
        high = mid - 1

return result

[Jatkingmodern]

can solve this issue in ++ kindle assign it to me

[Jatkingmodern]

#include <bits/stdc++.h>
using namespace std;

bool canPlaceCows(const vector& stalls, int k, int distance) {
int count = 1; // place first cow
int lastPos = stalls[0];

for (int i = 1; i < stalls.size(); i++) {
    if (stalls[i] - lastPos >= distance) {
        count++;
        lastPos = stalls[i];
        if (count == k) return true;
    }
}
return false;

}

int aggressiveCows(vector& stalls, int k) {
sort(stalls.begin(), stalls.end());
int low = 1;
int high = stalls.back() - stalls.front();
int result = 0;

while (low <= high) {
    int mid = (low + high) / 2;
    if (canPlaceCows(stalls, k, mid)) {
        result = mid;      // possible answer
        low = mid + 1;     // try for bigger distance
    } else {
        high = mid - 1;    // try smaller distance
    }
}
return result;

}

int main() {
vector stalls = {1, 2, 8, 4, 9};
int k = 3;
cout << aggressiveCows(stalls, k) << endl; // Example usage
return 0;
}
Could you tell me in which parrticular file to add this C++ code.