NectarWeb

How do I parse XML in Python ?


minidom is the quickest and pretty straight forward:

XML:

<data>
    <items>
        <item name="item1"></item>
        <item name="item2"></item>
        <item name="item3"></item>
        <item name="item4"></item>
    </items>
</data>
PYTHON:

from xml.dom import minidom
xmldoc = minidom.parse('items.xml')
itemlist = xmldoc.getElementsByTagName('item')
print(len(itemlist))
print(itemlist[0].attributes['name'].value)
for s in itemlist:
    print(s.attributes['name'].value)
OUTPUT

4
item1
item1
item2
item3
item4
------------------------------------------------------------------------------------------------------


How do I download a file over HTTP using Python ?


>>> import requests
>>> 
>>> url = "http://download.thinkbroadband.com/10MB.zip"
>>> r = requests.get(url)
>>> print len(r.content)
10485760

//
import urllib2
mp3file = urllib2.urlopen("http://www.example.com/songs/mp3.mp3")
output = open('test.mp3','wb')
output.write(mp3file.read())
output.close()

An improved version of the PabloG code for Python 2/3:

from __future__ import ( division, absolute_import, print_function, unicode_literals )

import sys, os, tempfile, logging

if sys.version_info >= (3,):
    import urllib.request as urllib2
    import urllib.parse as urlparse
else:
    import urllib2
    import urlparse

def download_file(url, desc=None):
    u = urllib2.urlopen(url)

    scheme, netloc, path, query, fragment = urlparse.urlsplit(url)
    filename = os.path.basename(path)
    if not filename:
        filename = 'downloaded.file'
    if desc:
        filename = os.path.join(desc, filename)

    with open(filename, 'wb') as f:
        meta = u.info()
        meta_func = meta.getheaders if hasattr(meta, 'getheaders') else meta.get_all
        meta_length = meta_func("Content-Length")
        file_size = None
        if meta_length:
            file_size = int(meta_length[0])
        print("Downloading: {0} Bytes: {1}".format(url, file_size))

        file_size_dl = 0
        block_sz = 8192
        while True:
            buffer = u.read(block_sz)
            if not buffer:
                break

            file_size_dl += len(buffer)
            f.write(buffer)

            status = "{0:16}".format(file_size_dl)
            if file_size:
                status += "   [{0:6.2f}%]".format(file_size_dl * 100 / file_size)
            status += chr(13)
            print(status, end="")
        print()

    return filename

url = "http://download.thinkbroadband.com/10MB.zip"
filename = download_file(url)
print(filename)

//

One more, using urlretrieve:

import urllib
urllib.urlretrieve ("http://www.example.com/songs/mp3.mp3", "mp3.mp3")
Yet another one, with a "progressbar"

import urllib2

url = "http://download.thinkbroadband.com/10MB.zip"

file_name = url.split('/')[-1]
u = urllib2.urlopen(url)
f = open(file_name, 'wb')
meta = u.info()
file_size = int(meta.getheaders("Content-Length")[0])
print "Downloading: %s Bytes: %s" % (file_name, file_size)

file_size_dl = 0
block_sz = 8192
while True:
    buffer = u.read(block_sz)
    if not buffer:
        break

    file_size_dl += len(buffer)
    f.write(buffer)
    status = r"%10d  [%3.2f%%]" % (file_size_dl, file_size_dl * 100. / file_size)
    status = status + chr(8)*(len(status)+1)
    print status,

f.close()

------------------------------------------------------------------------------------------------------

http://stackoverflow.com/questions/tagged/python?page=17&sort=votes&pagesize=15
http://stackoverflow.com/questions/166506/finding-local-ip-addresses-using-pythons-stdlib

Finding local IP addresses using Python's stdlib ?
How can I find local IP addresses (i.e. 192.168.x.x or 10.0.x.x) in Python platform independently 
and using only the standard library?

==>

import socket
socket.gethostbyname(socket.gethostname())

//

I just found this but it seems a bit hackish, however they say tried it on *nix and I did on windows and it worked.

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.connect(("gmail.com",80))
print(s.getsockname()[0])
s.close()

//

import socket
print([ip for ip in socket.gethostbyname_ex(socket.gethostname())[2] if not ip.startswith("127.")][:1])

//

import socket
print([(s.connect(('8.8.8.8', 80)), s.getsockname()[0], s.close()) for s in [socket.socket(socket.AF_INET, socket.SOCK_DGRAM)]][0][1])

------------------------------------------------------------------------------------------------------- 

What is the quickest way to HTTP GET in Python ?

import urllib.request
urllib.request.urlopen("http://example.com/foo/bar").read()

//

You could use a library called requests.

import requests
r = requests.get("http://example.com/foo/bar")
This is quite easy. Then you can do like this:

>>> print r.status_code
>>> print r.headers
>>> print r.content
-------------------------------------------------------------------------------------------------------