Error in any graph

[egolep]

For any graph I try to use, I get errors. For example, trying to use a catplot I get:

ERROR: PyError ($(Expr(:escape, :(ccall(#= /home/egolep/.julia/packages/PyCall/BD546/src/pyfncall.jl:43 =# @pysym(:PyObject_Call), PyPtr, (PyPtr, PyPtr, PyPtr), o, pyargsptr, kw))))) <class 'TypeError'>
TypeError("'PyCall.jlwrap' object is not subscriptable")
File "/home/egolep/.local/lib/python3.9/site-packages/seaborn/_decorators.py", line 46, in inner_f
return f(**kwargs)
File "/home/egolep/.local/lib/python3.9/site-packages/seaborn/regression.py", line 605, in lmplot
data = data[cols]

Stacktrace:
[1] pyerr_check
@ ~/.julia/packages/PyCall/BD546/src/exception.jl:62 [inlined]
[2] pyerr_check
@ ~/.julia/packages/PyCall/BD546/src/exception.jl:66 [inlined]
[3] _handle_error(msg::String)
@ PyCall ~/.julia/packages/PyCall/BD546/src/exception.jl:83
[4] macro expansion
@ ~/.julia/packages/PyCall/BD546/src/exception.jl:97 [inlined]
[5] #107
@ ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:43 [inlined]
[6] disable_sigint
@ ./c.jl:458 [inlined]
[7] __pycall!
@ ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:42 [inlined]
[8] _pycall!(ret::PyObject, o::PyObject, args::Tuple{}, nargs::Int64, kw::PyObject)
@ PyCall ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:29
[9] _pycall!
@ ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:11 [inlined]
[10] (::PyObject)(; kwargs::Base.Iterators.Pairs{Symbol, DataFrames.DataFrame, Tuple{Symbol}, NamedTuple{(:data,), Tuple{DataFrames.DataFrame}}})
@ PyCall ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:86
[11] lmplot(; kwargs::Base.Iterators.Pairs{Symbol, DataFrames.DataFrame, Tuple{Symbol}, NamedTuple{(:data,), Tuple{DataFrames.DataFrame}}})
@ Seaborn ~/.julia/packages/Seaborn/vfmph/src/Seaborn.jl:61
[12] top-level scope
@ REPL[53]:1

Or for a lmplot I get:

ERROR: PyError ($(Expr(:escape, :(ccall(#= /home/egolep/.julia/packages/PyCall/BD546/src/pyfncall.jl:43 =# @pysym(:PyObject_Call), PyPtr, (PyPtr, PyPtr, PyPtr), o, pyargsptr, kw))))) <class 'TypeError'>
TypeError("'PyCall.jlwrap' object is not subscriptable")
File "/home/egolep/.local/lib/python3.9/site-packages/seaborn/_decorators.py", line 46, in inner_f
return f(**kwargs)
File "/home/egolep/.local/lib/python3.9/site-packages/seaborn/regression.py", line 605, in lmplot
data = data[cols]

Stacktrace:
[1] pyerr_check
@ ~/.julia/packages/PyCall/BD546/src/exception.jl:62 [inlined]
[2] pyerr_check
@ ~/.julia/packages/PyCall/BD546/src/exception.jl:66 [inlined]
[3] _handle_error(msg::String)
@ PyCall ~/.julia/packages/PyCall/BD546/src/exception.jl:83
[4] macro expansion
@ ~/.julia/packages/PyCall/BD546/src/exception.jl:97 [inlined]
[5] #107
@ ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:43 [inlined]
[6] disable_sigint
@ ./c.jl:458 [inlined]
[7] __pycall!
@ ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:42 [inlined]
[8] _pycall!(ret::PyObject, o::PyObject, args::Tuple{}, nargs::Int64, kw::PyObject)
@ PyCall ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:29
[9] pycall!(ret::PyObject, o::PyObject, args::Tuple{}, kwargs::Base.Iterators.Pairs{Symbol, Any, NTuple{7, Symbol}, NamedTuple{(:x, :y, :hue, :col, :data, :col_wrap, :height), Tuple{String, String, String, String, DataFrames.DataFrame, Int64, Int64}}})
@ PyCall ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:11
[10] ##114
@ ~/.julia/packages/PyCall/BD546/src/pyfncall.jl:86 [inlined]
[11] lmplot(; kwargs::Base.Iterators.Pairs{Symbol, Any, NTuple{7, Symbol}, NamedTuple{(:x, :y, :hue, :col, :data, :col_wrap, :height), Tuple{String, String, String, String, DataFrames.DataFrame, Int64, Int64}}})
@ Seaborn ~/.julia/packages/Seaborn/vfmph/src/Seaborn.jl:61
[12] top-level scope
@ REPL[56]:1

Is it a problem with my version o Python? I also tried to use PyCall with Conda instead of my system version of Python, but with no difference (I don't also know if Seaborn.jl actually uses PyCall)

[ShuhuaGao]

Note that the dataframe required by Seaborn.jl is Pandas.DataFrame instead of DataFrames.DataFrame. Check https://github.com/JuliaPy/Pandas.jl for details.

Run the official example in Julia 1.6.0:

import Seaborn as sns
tips = sns.load_dataset("tips")
typeof(tips) # Pandas.DataFrame

sns.boxplot(x="day", y="total_bill", data=tips)

[malmaud]

@ShuhuaGao is right. I would support a feature that autoconverts the input to Seaborn functions from DataFrames.DataFrame to Pandas.DataFrame so your example would work seamlessly - PRs welcome!

[ShuhuaGao]

autoconverts the input to Seaborn functions from DataFrames.DataFrame to Pandas.DataFrame

Pandas supports such manual conversion. For now, I suggest mentioning this issue and the workaround in the README. I encountered this issue at the beginning as well and thought that DataFrames.DataFrame was allowed.

julia> using DataFrames

julia> import Pandas as pd

julia> jdf = DataFrame(x=[1, 2], y=[2.3, -1]);

julia> pd.DataFrame(jdf)  # to Pandas.DataFrame
     y  x
0  2.3  1
1 -1.0  2

[egolep]

Thanks to everyone