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37.cpp
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#include <bits/stdc++.h>
using namespace std;
class Solution {
public:
/**
* Leetcode题解【解数独】回溯 + 状态压缩(使用 bitset)
*/
void solveSudoku(vector<vector<char>>& board) {
rows = vector<bitset<9>>(9, bitset<9>()); // 行的标记, 一行9个
cols = vector<bitset<9>>(9, bitset<9>()); // 列的标记
cells = vector<vector<bitset<9>>>(3, vector<bitset<9>>(3, bitset<9>())); // cell 部分, 记录数字
int cnt = 0; // 计数单元,记录有多少个待填的数
int n = board.size(), m = board[0].size();
for (int i=0; i < n; ++i) {
for (int j=0; j < m; ++j) {
cnt += (board[i][j] == '.');
if (board[i][j] == '.') continue;
int n = board[i][j] - '1'; // 1-9 => 0-8
rows[i] |= (1<<n); // 标记已经选择的数
cols[j] |= (1<<n); // 标记已经选择的数
cells[i/3][j/3] |= (1<<n); // cells中标记已经选择的数
}
}
dfs(board, cnt);
}
bool dfs(vector<vector<char>>& board, int cnt) {
if (cnt == 0) return true;
auto next = getNext(board);
auto bits = getPossibleStatus(next[0], next[1]);
for (int n = 0; n < bits.size(); ++n) {
if (!bits.test(n)) continue; // continue
fillNum(next[0], next[1], n, true); // 标记
board[next[0]][next[1]] = n+'1';
if (dfs(board, cnt - 1)) return true;
board[next[0]][next[1]] = '.';
fillNum(next[0], next[1], n, false); // 恢复
}
return false;
}
vector<int> getNext(vector<vector<char>>& board) {
vector<int> ret;
int minCnt = 10; // 元素个数
int n = board.size(), m = board[0].size();
for (int i=0; i < n; ++i) {
for (int j=0; j < m; ++j) {
if (board[i][j] != '.') continue;
auto cur = getPossibleStatus(i, j); // 还没填的位置,获取其 可以填啥
// 找到最小范围的位置
if (cur.count() >= minCnt) continue; // 如果没有
ret = {i, j};
minCnt = cur.count(); // 或者set位置
}
}
return ret;
}
bitset<9> getPossibleStatus(int x, int y) {
return ~(rows[x] | cols[y] | cells[x/3][y/3]); // get 未标记的
}
void fillNum(int x, int y, int n, bool fillFlag) {
rows[x][n] = (fillFlag)? 1:0;
cols[y][n] = (fillFlag)? 1:0;
cells[x/3][y/3][n] = (fillFlag)? 1:0;
}
private:
vector<bitset<9>> rows;
vector<bitset<9>> cols;
vector<vector<bitset<9>>> cells;
};