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| 1 | +//! 层序遍历 |
| 2 | +use datastructure::TreeNode; |
| 3 | +use std::cell::RefCell; |
| 4 | +use std::rc::Rc; |
| 5 | + |
| 6 | +/// [2583. 二叉树中的第 K 大层和](https://leetcode.cn/problems/kth-largest-sum-in-a-binary-tree/) |
| 7 | +pub fn kth_largest_level_sum(root: Option<Rc<RefCell<TreeNode>>>, k: i32) -> i64 { |
| 8 | + use std::collections::{BinaryHeap, VecDeque}; |
| 9 | + |
| 10 | + let mut heap = BinaryHeap::new(); |
| 11 | + let mut travel_queue = VecDeque::new(); |
| 12 | + |
| 13 | + travel_queue.push_back(root); |
| 14 | + |
| 15 | + // let mut lvl = 0; |
| 16 | + while !travel_queue.is_empty() { |
| 17 | + let mut lvl_sum = 0i64; |
| 18 | + |
| 19 | + for _ in 0..travel_queue.len() { |
| 20 | + if let Some(node) = travel_queue.pop_front().unwrap() { |
| 21 | + let node = node.borrow(); |
| 22 | + lvl_sum += node.val as i64; |
| 23 | + if let Some(left) = &node.left { |
| 24 | + travel_queue.push_back(Some(left.clone())); |
| 25 | + } |
| 26 | + if let Some(right) = &node.right { |
| 27 | + travel_queue.push_back(Some(right.clone())); |
| 28 | + } |
| 29 | + } |
| 30 | + } |
| 31 | + // println!("lvl: {}, lvl_sum: {}", lvl, lvl_sum); |
| 32 | + heap.push(lvl_sum); |
| 33 | + // lvl += 1; |
| 34 | + } |
| 35 | + // dbg!("heap", &heap); |
| 36 | + if heap.len() < k as usize { |
| 37 | + -1 |
| 38 | + } else { |
| 39 | + heap.into_sorted_vec() |
| 40 | + .into_iter() |
| 41 | + .rev() |
| 42 | + .nth(k as usize - 1) |
| 43 | + .unwrap() |
| 44 | + } |
| 45 | +} |
| 46 | + |
| 47 | +#[cfg(test)] |
| 48 | +mod tests { |
| 49 | + use super::*; |
| 50 | + use macros::tree; |
| 51 | + |
| 52 | + #[test] |
| 53 | + fn test_kth_largest_level_sum() { |
| 54 | + struct TestCase { |
| 55 | + tree: Option<Rc<RefCell<TreeNode>>>, |
| 56 | + k: i32, |
| 57 | + expected: i64, |
| 58 | + } |
| 59 | + vec![ |
| 60 | + TestCase{ |
| 61 | + tree: tree!{val:5, left: {val: 8, left: {val: 2, left: {val: 4}, right: {val: 6}}, right: {val: 1}}, right: {val: 9, left: {val: 3}, right: {val: 7}}}, |
| 62 | + k: 2, |
| 63 | + expected: 13, |
| 64 | + }, |
| 65 | + TestCase{ |
| 66 | + tree: tree!{val: 1, left: {val: 2, left: {val:3}}}, |
| 67 | + k: 1, |
| 68 | + expected: 3 |
| 69 | + } |
| 70 | + |
| 71 | + ].into_iter().enumerate().for_each(|(idx, TestCase{tree, k, expected})|{ |
| 72 | + let actual = kth_largest_level_sum(tree.clone(), k); |
| 73 | + assert_eq!(actual, expected, "Test case {} failed", idx+1); |
| 74 | + }); |
| 75 | + } |
| 76 | +} |
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