See the discussion here #67 (comment)
If you want to reconstruct an image centered in [x,y] you can equivalently:
- have
phase_center = [x,y] and create a meshgrid X,Y centerd in [0,0]
- have
phase_center = [0,0] and create a meshgrid X,Y centered in [x,y]
- In general, have
phase_center = [x',y'] and create a meshgrid X,Y centerd in [x - x',y - > y'] (or, maybe, [x' - x,y' - y]; it does not matter for this discussion)
Also given a Visibility $V$ and a new visibility $V' = \phi V$ created by applying and complex phase shift $\phi$ its not possible to go back to $V$ as given only $V'$ as $\phi$ is not stored in $V'`$
So we need to store two items the values used to generate the mesh grid the phase shift as this make 3 and solve the reversibly problem, both can be represented as pairs of $[x, y]$ coordinates.
Possible naming conventions:
phase_reference, phase_offset
phase_center, phase_reference
phase_center, phase_offset
phase_center=[x, y], phase_reference=[0,0]
phase_center=[0, 0], phase_reference=[x,y]
phase_center=[x', y'], phase_reference=[x-x',y-y'] ?
See the discussion here #67 (comment)
Also given a Visibility$V$ and a new visibility $V' = \phi V$ created by applying and complex phase shift $\phi$ its not possible to go back to $V$ as given only $
V'$ as $\phi$ is not stored in $V'`$So we need to store two items the values used to generate the mesh grid the phase shift as this make 3 and solve the reversibly problem, both can be represented as pairs of$[x, y]$ coordinates.
Possible naming conventions:
phase_reference, phase_offset
phase_center, phase_reference
phase_center, phase_offset
phase_center=[x, y],phase_reference=[0,0]phase_center=[0, 0],phase_reference=[x,y]phase_center=[x', y'],phase_reference=[x-x',y-y']?