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The loop invariant invariant xxx will be transferred into the form of assert XXX in the smack-generated boogie code (from c code). I wonder the form of free loop invariant free invariant XXX in the smack-generated boogie code.
@zvonimir : This is really a SMACK question and should have been posted on the SMACK (if it has one). But please provide some answer here to help out @Luweicai .
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The loop invariant
invariant xxxwill be transferred into the form ofassert XXXin the smack-generated boogie code (from c code). I wonder the form of free loop invariantfree invariant XXXin the smack-generated boogie code.All reactions