How to cleanly match only one of distinct sets of arguments in clap?

[GaurangTandon]

I have exactly three distinct sets of arguments that can be passed to my binary. Let's label them like this:

1. foo <int> <int>
2. bar <int>
3. baz <string>

As you can see, they are completely different. For now, I plan to do the following:

let app = App::new()...;
let args1 = app.arg(set1).get_matches();
let args2 = app.arg(set2).get_matches();
let args3 = app.arg(set3).get_matches();

While this may work (haven't tested yet), main problem I have is:

1. It does not ensure that exactly one of foo/bar/baz is required. If I pass .required(true) in any of these sets, then the whole binary would abort with an error message.
2. I'll have to manually add validation in case more than one of these sets match.

Is there a cleaner way to do this in clap, which handles at least the above two points? I have gone through the docs more than once, but I definitely did not find anything there that handles this, but that's likely because the docs are too dense and comprehensive, and I do not even know what to look for :/

[ldm0]

Have you checked the subcommand?

[GaurangTandon]

Thanks, it seems to be exactly what I need. How to ensure exclusion between different subcommands? I presume we cannot use ArgGroups in this case?

[ldm0]

Please check SubcommandPrecedenceOverArg.

[ldm0]

And also: ArgsNegateSubcommands.