1-answer.md

✅ Lowercase Alphanumeric to solve the 🧑🏻‍💻 Valid Palindrome Problem on 🦀 Python language

🧑🏻‍💻 Approach

The Solution struct contains a public function is_palindrome that takes a String parameter s and returns a boolean value. The goal of the function is to determine if the given string s is a palindrome.

The solution first converts the string s to lowercase using the to_lowercase method, storing the result in the variable a. This step is necessary to perform a case-insensitive comparison.

Next, the characters of a are collected into a vector b using the chars method. Each character is filtered using the retain method, which removes whitespace and punctuation characters from b. This is achieved by keeping only the characters for which the closure condition !x.is_whitespace() && !x.is_ascii_punctuation() returns true.

To check if the string is a palindrome, a clone of b is created in the variable c. The reverse method is then used to reverse the order of characters in c.

Finally, an if statement compares the vectors b and c. If they are equal, it means that the original string s is a palindrome, so the function returns true. Otherwise, it returns false.

🔐 Code

impl Solution {
    pub fn is_palindrome(s: String) -> bool {
        let a = s.to_lowercase();
    let mut b = a.chars().collect::<Vec<char>>();
    b.retain(|&x| !x.is_whitespace() && !x.    is_ascii_punctuation());

    let mut c = b.clone();
    c.reverse();
    if b == c{
       return true;
    }
       return false;
    }
}