017._letter_combinations_of_a_phone_number.md

17. Letter Combinations of a Phone Number

难度: Medium

刷题内容

原题连接

• https://leetcode.com/problems/letter-combinations-of-a-phone-number/description/

内容描述

Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.



Example:

Input: "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
Note:

Although the above answer is in lexicographical order, your answer could be in any order you want.

解题方案

思路 1

• hash table一个，用来对应digit -> letter
• s用来记录结果，每次从digits里面去一个，然后寻找其可能的char，加到s中，digits长度减小
• digits长度为0时候，把它加入结果

class Solution(object):
    def letterCombinations(self, digits):
        """
        :type digits: str
        :rtype: List[str]
        """
        lookup = {
            '2':['a','b','c'],
            '3':['d','e','f'],
            '4':['g','h','i'],
            '5':['j','k','l'],
            '6':['m','n','o'],
            '7':['p','q','r','s'],
            '8':['t','u','v'],
            '9':['w','x','y','z']
        }
        res = []
        
        def helper(s, digits):
            if len(digits) == 0:
                res.append(s)
            else:
                cur_digit = digits[0]
                for char in lookup[cur_digit]:
                    helper(s+char, digits[1:])
                    
        if not digits or len(digits) == 0:
            return res
        helper('', digits)
        return res