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.travis.yml

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@@ -37,8 +37,6 @@ script:
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- cd ../probability-theory_16-17_2course
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- pdflatex -interaction=nonstopmode -halt-on-error -output-directory ../_build probability-theory_16-17_2course_lectures.tex
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- pdflatex -interaction=nonstopmode -halt-on-error -output-directory ../_build probability-theory_16-17_2course_lectures.tex
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- pdflatex -interaction=nonstopmode -halt-on-error -output-directory ../_build probability-theory_16-17_2course_seminars.tex
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- pdflatex -interaction=nonstopmode -halt-on-error -output-directory ../_build probability-theory_16-17_2course_seminars.tex
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- pdflatex -interaction=nonstopmode -halt-on-error -output-directory ../_build probability-theory_16-17_2course_raidboss.tex
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- pdflatex -interaction=nonstopmode -halt-on-error -output-directory ../_build probability-theory_16-17_2course_raidboss.tex
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- cd ..

probability-theory_16-17_2course/raidboss-lectures/lecture_raidboss_07_07.03.2017.tex

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@@ -46,7 +46,7 @@ \subsection{Пороговые функции}
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Вынесем $(1 - p'')^{\binom{n}{2} - |E(G)|} (1 - p')^{\binom{n}{2} - |E(G)|} =
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(1 - p' - p'' + p'p'')^{\binom{n}{2} - |E(G)|}$, что даёт один множитель. А теперь
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давайте посчитаем оставшийся множитель:
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давайте посчитаем оставшийся множитель (благо, всё сходится):
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\[
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\sum\limits_{m = 0}^{|E(G)|} \binom{|E(G)|}{m}p'^mp''^{|E(G)| - m}(1 -

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