Several conditions for entity icon color

[rom169]

Hi,
trying several conditions to change icon color of entities.

Single condition works:
type: custom:room-card
title: Test
entity: light.lightsstairsegug_2
show_icon: true
info_entities:

• entity: binary_sensor.sensordoormain_window_door_is_open
  show_icon: true
  icon:
  template:
  styles: |
  if (entity.state == 'on') return 'color: mediumseagreen';

Any hint on how to make something like this work:
type: custom:room-card
title: Test
entity: light.lightsstairsegug_2
show_icon: true
info_entities:

• entity: binary_sensor.sensordoormain_window_door_is_open
  show_icon: true
  icon:
  template:
  styles: >
  if ((entity.state == 'on') and (states('binary_sensor.anybody_home') == 'on')) return 'color: mediumseagreen';
  if ((entity.state == 'on') and (states('binary_sensor.anybody_home') == 'off')) return 'color: cyan';

Thanks

[marcokreeft87]

Try else if as second condition or just use conditions like in the wiki

[rom169]

What I want to realize is not an else, I need an AND of two states, one of the entity I'm using in the card and one of another entity:
if ((entity.state == 'on') and (states('binary_sensor.anybody_home') == 'on')) return 'color: mediumseagreen';

I could do that by creating an additional sensor, but although it is covered by the documentation, using icon templating states results in a card syntax error:
if (states('binary_sensor.anybody_home') == 'on') return 'color: mediumseagreen';

[marcokreeft87]

Try using && instead of 'and'

[rom169]

Did some more testing. This syntax is working:
if ((entity.state == 'on') & (states['binary_sensor.anybody_home'].state == 'on' )) return 'color: mediumseagreen';

[marcokreeft87]

I'd change it to && so double &. A single & does bitwise and.