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Per bug 4695 clarify question and solution
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  • OpenProblemLibrary/Indiana/Indiana_setSeries5IntegralTest

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OpenProblemLibrary/Indiana/Indiana_setSeries5IntegralTest/ur_sr_5_11.pg

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@@ -8,7 +8,7 @@
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## DBchapter(Infinite sequences and series)
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## DBsection(Integral test)
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## Date(6/3/2002)
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## Institution(Univeristy of Utah)
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## Institution(University of Utah)
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## Author(Utah ww group)
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## Level(2)
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## TitleText1('Calculus')
@@ -157,13 +157,15 @@ qa(~~@questions, ~~@answers,
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($ans1, $ans2, $ans3, $ans4, $ans5) = @answers[@slice] ;
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TEXT(EV3(<<'EOT'));
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Test each of the following series for convergence by the Integral Test.
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If the Integral Test can be applied to the series, enter CONV if
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Test each of the following series for convergence by the Integral Test. (Don't use any other tests.)
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If the Integral Test, by itself, can be applied to the series to determine whether it converges, enter CONV if
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it converges or DIV if it diverges.
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If the integral test cannot be applied to the series, enter NA.
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(Note: this means that even if you know a given series converges
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by some other test, but the Integral Test cannot be applied to it,
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then you must enter NA rather than CONV.) $BR $BR
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$PAR(Note: this means that even if you know a given series converges
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by using some other test, or some other test combined with the integral test,
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but the integral test, all by itself, does not determine the answer
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then you must enter NA rather than CONV.) $PAR
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EOT
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TEXT(EV2(match_questions_list_varbox(10,@questions[@slice])));
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@@ -311,8 +313,12 @@ EOT
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if ($slice[$i] == 5) {
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&SOLUTION(EV3(<<'EOT'));
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($j). The function \(f(x) = \frac{x+$f}{\left(-$g\right)^x}\) oscillates between
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positive and negative values due to its denominator, so the Integral Test
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does not apply.
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positive and negative values due to its denominator, so the integral test
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does not apply directly, so NA is the correct answer.
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$PAR (However the integral test can be used to show that the series converges $BBOLD absolutely
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$EBOLD, so the additional fact that $BQUOTE absolute convergence implies convergence $EQUOTE
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shows that the series does, in fact, converge.)
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EOT
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}

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