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ArrayList vs LinkedList in Java — when to use which? #1
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Hi everyone, I'm trying to understand the practical difference between Specifically:
Would appreciate insights from anyone who's hit performance issues with either in production code. Thanks! |
Replies: 1 comment
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Great question! Here's a practical breakdown: Where LinkedList actually wins: Insertion/deletion performance in practice: Big-O says LinkedList insert/delete is O(1) vs ArrayList's O(n) — but that's only true if you already have the node reference. If you're searching for the position first (get(index)), that search itself is O(n) for LinkedList (no random access), so you lose the advantage. Is there ever a good reason to use LinkedList? When implementing a Deque/queue-like structure with constant add/remove from both ends (addFirst, removeLast, etc.) For 95% of use cases — including most CRUD apps, lists of objects, iteration-heavy code — ArrayList (or ArrayDeque if you need queue behavior) is the better default. Memory overhead is also a factor: each LinkedList node carries extra pointer overhead (prev/next references), so it uses more memory per element too. TL;DR: Default to ArrayList unless you're specifically building a deque/queue with two-ended access patterns — then use ArrayDeque, which usually beats LinkedList even for that. |
Great question! Here's a practical breakdown:
Where LinkedList actually wins:
Honestly, in modern Java, real-world cases where LinkedList clearly outperforms ArrayList are rare. The main scenario is when you're doing frequent insertions/deletions at the beginning or middle of a large list, and you already have a reference (iterator) at that position — like implementing a custom queue/deque where you're constantly adding/removing from both ends. That's actually why LinkedList implements Deque.
Insertion/deletion performance in practice:
Big-O says LinkedList insert/delete is O(1) vs ArrayList's O(n) — but that's only true if you already have the node reference. If you're searching for the …