FreeBSD /bin/sh have no option '-l'

[rosso-]

Non-zero exit code from shell /bin/sh invoked with args ("-l" "-i" "-c" "/usr/bin/printf '__RESULT\\000%s\\000%s\\000__RESULT' \"${PATH-2bfaad800615049564580\
26191a73346}\" \"${MANPATH-2bfaad80061504956458026191a73346}\"").  Output was:
"Illegal option -l
"

I got this output from exec-path-from-shell on FreeBSD13.
Ther is no such an option on FreeBSD's /bin/sh.
Can we do something with it?

[purcell]

Interesting. Which shell is /bin/sh on FreeBSD? You can certainly override exec-path-from-shell-arguments to remove -l from the defaults in this case.

[dertuxmalwieder]

Which shell is /bin/sh on FreeBSD?

A variant of the Almquist shell, mostly.