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binarytree_zigzag_levelorder_traversal.cpp
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/*
Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[
[3],
[20,9],
[15,7]
]
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> zigzagLevelOrder(TreeNode* root) {
vector<vector<int>> ret;
if(root==NULL)
return ret;
vector<TreeNode *> fringe;
int depth = 0;
int fringe_pos = 0;
int next_itr = 1;
fringe.push_back(root);
while(next_itr != 0)
{
vector<int> tmp;
if(depth%2!=0)
{
int j = fringe_pos + next_itr - 1;
while(j>=fringe_pos)
{
tmp.push_back(fringe[j]->val);
j--;
}
}
else
{
int j = fringe_pos;
while (j<=(fringe_pos + next_itr - 1))
{
tmp.push_back(fringe[j]->val);
j++;
}
}
ret.push_back(tmp);
int i = next_itr;
next_itr = 0;
TreeNode *cur;
for(int j=0;j<i;j++)
{
cur=fringe[fringe_pos];
if(cur->left!=NULL)
{
fringe.push_back(cur->left);
next_itr++;
}
if(cur->right!=NULL)
{
fringe.push_back(cur->right);
next_itr++;
}
fringe_pos++;
}
depth++;
}
return ret;
}
};