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MinIndexDiff.java
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37 lines (34 loc) · 1.25 KB
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//(G) Given an array of integers that only contains values 0,1,2;
// find the minimum index difference between a 1 and a 2. Formally,
// minimize abs(i - j) s.t. A[i] == 1 and A[j] == 2
public class MinIndexDiff {
public static int findMinIndexDiff(int[] arr) {
int index1 = -1;
int index2 = -1;
int minIndex = Integer.MAX_VALUE;
boolean index1Updated = false;
boolean index2Updated = false;
for (int i = 0; i < arr.length; ++i) {
if (arr[i] == 1) {
index1 = i;
index1Updated = true;
}
if (arr[i] == 2) {
index2 = i;
index2Updated = true;
}
if (index1 != -1 && index2 != -1 && (index1Updated || index2Updated)) {
minIndex = Math.min(minIndex, Math.abs(index1 - index2));
index1Updated = false;
index2Updated = false;
}
}
return minIndex;
}
public static void main(String[] args) {
int[] input = {0,2,0,1,2,0,1,2,2,0,0,1};
int[] input1 = {0,1,0,1,1,0,1,0,0,0,2,2};
System.out.println(MinIndexDiff.findMinIndexDiff(input));
System.out.println(MinIndexDiff.findMinIndexDiff(input1));
}
}