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Copy pathDay-17-Robot Bounded In Circle.cpp
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Day-17-Robot Bounded In Circle.cpp
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On an infinite plane, a robot initially stands at (0, 0) and faces north. The robot can receive one of three instructions:
"G": go straight 1 unit;
"L": turn 90 degrees to the left;
"R": turn 90 degress to the right.
The robot performs the instructions given in order, and repeats them forever.
Return true if and only if there exists a circle in the plane such that the robot never leaves the circle.
Example 1:
Input: "GGLLGG"
Output: true
Explanation:
The robot moves from (0,0) to (0,2), turns 180 degrees, and then returns to (0,0).
When repeating these instructions, the robot remains in the circle of radius 2 centered at the origin.
Example 2:
Input: "GG"
Output: false
Explanation:
The robot moves north indefinitely.
Example 3:
Input: "GL"
Output: true
Explanation:
The robot moves from (0, 0) -> (0, 1) -> (-1, 1) -> (-1, 0) -> (0, 0) -> ...
Note:
1 <= instructions.length <= 100
instructions[i] is in {'G', 'L', 'R'}
Hide Hint #1
Calculate the final vector of how the robot travels after executing all instructions once - it consists of a change in position plus a change in direction.
Hide Hint #2
The robot stays in the circle iff (looking at the final vector) it changes direction (ie. doesn't stay pointing north), or it moves 0.
class Solution {
public:
bool isRobotBounded(string instructions) {
int n=instructions.length();
int dir=0; // 0-N, 1-E, 2-S, 3-W
int x=0, y=0;
for(int i=0;i<n;i++){
if(instructions[i]=='G'){
if(dir==0) y++;
else if(dir==1) x--;
else if(dir==2) y--;
else x++;
} else if(instructions[i]=='L'){
if(dir==0) dir=1;
else if(dir==1) dir=2;
else if(dir==2) dir=3;
else dir=0;
} else if(instructions[i]=='R'){
if(dir==0) dir=3;
else if(dir==1) dir=0;
else if(dir==2) dir=1;
else dir=2;
}
}
if(x==0 && y==0) return true;
else if(dir!=0) return true;
else return false;
}
};