scrabble.py

import argparse

def scrabble(rack):
    valid_words = []
    l = []
    dic = {}
    ans = []
    score = 0
    scores = {"a": 1, "c": 3, "b": 3, "e": 1, "d": 2, "g": 2,   
             "f": 4, "i": 1, "h": 4, "k": 5, "j": 8, "m": 3,
             "l": 1, "o": 1, "n": 1, "q": 10, "p": 3, "s": 1,
             "r": 1, "u": 1, "t": 1, "w": 4, "v": 4, "y": 4,
             "x": 8, "z": 10}                       #dict of the scores assigned to each English alphabet

    ##### Argument parser 
    """parser = argparse.ArgumentParser()   
    parser.add_argument("echo", help="Echo the wrack of letters", type=str)
    args = parser.parse_args()
    print args.echo
    rack = args.echo"""

    #rack = raw_input('Enter rack of words: ').lower()       #taking rack of word from the user
    fp = open('sowpods.txt', 'r')                           #reading SOWPODS file

    for line in fp.readlines():
        flag = 0
        dup_rack = rack
        word = line.strip()                         #Handling every valid word in the file
        for letter in word.lower():
            if letter not in dup_rack:
                flag = 1
                break
            elif letter in dup_rack:
                dup_rack = dup_rack.replace(letter, '')     #removing the letter that is already checked from rack var
        if flag == 0:
            valid_words.append(word.lower())                #list of all the valid words


    fp.close()
    for word in set(valid_words):
        for letter in word.lower():
            score += scores[letter]                 #calculating the scores per word
        dic.update({word : score})                  #adding valid words with their scores to the dictionary 
        score = 0

    '''if dic == {}:
        print No valid word found!'''
    if dic != {}:
        for key in sorted(dic):
            ans.append((dic[key], key))                         #printing score and valid word pair from the dict
        return ans

if __name__ == '__main__':
    print scrabble('wfevrbrebb')