PythonPractice/*args **args.py at master · uzairiqbal91/PythonPractice · GitHub

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#!/usr/bin/env python
# coding: utf-8

# In[1]:


# function witout arguement and return void
def my_fun():
    print("hello world")


my_fun()

# function with arguement and return void
def my_func_withparam(name):
    print(name)

my_func_withparam("uzair")

def my_func_withparam_default(name = "UZAIR"):
    print(name)

my_func_withparam_default()

my_name = my_func_withparam("Uzair")
print(type(my_name))
# it will return NoneType so the reutrn type of my_name is Void


# function with arguement and return Int
def add_two_number(num1,num2):
    return num1+num2


addVal = add_two_number(2,4)

print(type(addVal))
# it will return Int so the reutrn type of addVal is Int

# **args
# it takes an arguemetns as dictionary

def my_func_dict(**args):
    return args

# you can not call this by simple my_func_dict(4) because it must take dictionary
print(my_func_dict(val = 4)['val'])


# In[ ]:


# In[ ]: