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40.combination-sum-ii.go
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import "sort"
/*
* @lc app=leetcode id=40 lang=golang
*
* [40] Combination Sum II
*
* https://leetcode.com/problems/combination-sum-ii/description/
*
* algorithms
* Medium (48.33%)
* Likes: 1914
* Dislikes: 71
* Total Accepted: 340.6K
* Total Submissions: 703.5K
* Testcase Example: '[10,1,2,7,6,1,5]\n8'
*
* Given a collection of candidate numbers (candidates) and a target number
* (target), find all unique combinations in candidates where the candidate
* numbers sums to target.
*
* Each number in candidates may only be used once in the combination.
*
* Note:
*
*
* All numbers (including target) will be positive integers.
* The solution set must not contain duplicate combinations.
*
*
* Example 1:
*
*
* Input: candidates = [10,1,2,7,6,1,5], target = 8,
* A solution set is:
* [
* [1, 7],
* [1, 2, 5],
* [2, 6],
* [1, 1, 6]
* ]
*
*
* Example 2:
*
*
* Input: candidates = [2,5,2,1,2], target = 5,
* A solution set is:
* [
* [1,2,2],
* [5]
* ]
*
*
*/
// @lc code=start
func combinationSum2(candidates []int, target int) [][]int {
return combinationSum21(candidates, target)
}
func combinationSum21(candidates []int, target int) [][]int {
sort.Ints(candidates)
res := [][]int{}
dfs(&res, candidates, []int{}, 0, target)
return res
}
func dfs(res *[][]int, candidates, cur []int, index, target int) {
if target < 0 {
return
} else if target == 0 {
*res = append(*res, append([]int{}, cur...))
} else {
for i := index; i < len(candidates); i++ {
if i == index || candidates[i] != candidates[i-1] { // don't add duplicate element
dfs(res, candidates, append(cur, candidates[i]), i+1, target-candidates[i])
}
}
}
}
// @lc code=end