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Problem_0101_isSymmetric.cc
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#include <vector>
#include "UnitTest.h"
using namespace std;
struct TreeNode
{
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
};
class Solution
{
public:
void inorder(TreeNode *cur, vector<int> &ans, int i)
{
if (cur == nullptr)
{
// 记录空节点,防止节点出现相同元素
// 1
// ↙ ↘
// 2 2
// ↙ ↘ ↙
// 2 N 2
ans.push_back(101 + i);
return;
}
inorder(cur->left, ans, i + 1);
ans.push_back(cur->val);
inorder(cur->right, ans, i + 1);
}
bool isSymmetric1(TreeNode *root)
{
vector<int> ans;
inorder(root, ans, 0);
int n = ans.size();
for (int i = 0; i <= n / 2; i++)
{
if (ans[i] != ans[n - 1 - i])
{
return false;
}
}
return true;
}
// 一颗是原始树
// 一颗是翻面树
bool isMirror(TreeNode *head1, TreeNode *head2)
{
if (head1 == nullptr && head2 == nullptr)
{
return true;
}
if (head1 != nullptr && head2 != nullptr)
{
return head1->val == head2->val && isMirror(head1->left, head2->right) && isMirror(head1->right, head2->left);
}
// 一个为空,一个不为空 false
return false;
}
bool isSymmetric2(TreeNode *root) { return isMirror(root, root); }
};
void testIsSymmetric()
{
Solution s;
TreeNode *x7 = new TreeNode(3, nullptr, nullptr);
TreeNode *x6 = new TreeNode(4, nullptr, nullptr);
TreeNode *x5 = new TreeNode(4, nullptr, nullptr);
TreeNode *x4 = new TreeNode(3, nullptr, nullptr);
TreeNode *x3 = new TreeNode(2, x6, x7);
TreeNode *x2 = new TreeNode(2, x4, x5);
TreeNode *x1 = new TreeNode(3, x2, x3);
TreeNode *y5 = new TreeNode(3, nullptr, nullptr);
TreeNode *y4 = new TreeNode(3, nullptr, nullptr);
TreeNode *y3 = new TreeNode(2, nullptr, y5);
TreeNode *y2 = new TreeNode(2, nullptr, x4);
TreeNode *y1 = new TreeNode(1, y2, y3);
EXPECT_TRUE(s.isSymmetric1(x1));
EXPECT_FALSE(s.isSymmetric1(y1));
EXPECT_TRUE(s.isSymmetric2(x1));
EXPECT_FALSE(s.isSymmetric2(y1));
EXPECT_SUMMARY;
}
int main()
{
testIsSymmetric();
return 0;
}