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This absolutely a good BFS solution here. Nice work!

nodes_hash = {}

dislikes.each do |dislike|
q.unshift(i) if !nodes_hash[i]

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I would use << or push instead of unshift. Just because you put things on the rear of a queue. It's functionally equivalent in this case, because the queue is empty, but it's not treating q like a queue.

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2 participants