Skip to content

Conversation

mobregong
Copy link

No description provided.

Copy link

@kyra-patton kyra-patton left a comment

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

✨ Nice work, Maria. I left some style suggestions, but it looks like you have a good grasp on linked lists. Let me know what questions you have.

🟢

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(1)
# Space Complexity: O(1)
def get_first(self):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(1)
# Space Complexity: O(1)
def add_first(self, value):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def search(self, value):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Comment on lines +64 to +69
if current_node.next:
current_node = current_node.next
else:
return length
else:
return length

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

🤓 Style suggestion to condense your code. Since your while condition is essentially to check if current_node is a Node object or None, just set current_node to current_node.next regardless of whether next is a Node or None.

If it's None, your while loop will finish executing and you can just return whatever length is at that point!

Suggested change
if current_node.next:
current_node = current_node.next
else:
return length
else:
return length
current_node = current_node.next
return length

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def get_at_index(self, index):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def add_last(self, value):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.


# method to return the max value in the linked list
# returns the data value and not the node
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_max(self):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def reverse(self):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(n)
def visit(self):

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Comment on lines +147 to +149
if current_node.value == value:
self.head = current_node.next
break

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

🤓I would suggest using return over break statements

Suggested change
if current_node.value == value:
self.head = current_node.next
break
if current_node.value == value:
self.head = current_node.next
return

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

Successfully merging this pull request may close these issues.

2 participants