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150 changes: 117 additions & 33 deletions linked_list/linked_list.py
Original file line number Diff line number Diff line change
Expand Up @@ -13,67 +13,135 @@ def __init__(self):

# returns the value in the first node
# returns None if the list is empty
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(1)
# Space Complexity: O(1)
def get_first(self):
pass
if not self.head:
return None
return self.head.value


# method to add a new node with the specific data value in the linked list
# insert the new node at the beginning of the linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(1)
# Space Complexity: O(1)
def add_first(self, value):
pass
new_node = Node(value)
new_node.next = self.head
self.head = new_node

# method to find if the linked list contains a node with specified value
# returns true if found, false otherwise
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def search(self, value):
pass
current = self.head

while current:
if current.value== value:
return True
current = current.next

return False

# method that returns the length of the singly linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def length(self):
pass
count = 0
current = self.head

while current != None:
current = current.next
count +=1
return count

# method that returns the value at a given index in the linked list
# index count starts at 0
# returns None if there are fewer nodes in the linked list than the index value
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def get_at_index(self, index):
pass
if index < 0:
return None
else:
current = self.head
count = 0
while current:
if count == index:
return current.value
current = current.next
count += 1
return



# method that returns the value of the last node in the linked list
# returns None if the linked list is empty
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def get_last(self):
pass
current = self.head
if not current:
return None
while current.next:
current = current.next
else:
return current.value

# method that inserts a given value as a new last node in the linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def add_last(self, value):
pass
if not self.head :
self.add_first(value)
else:

node = Node(value)
current = self.head
while current.next:
current = current.next
current.next = node


# method to return the max value in the linked list
# returns the data value and not the node
def find_max(self):
pass
max = 0
if self.head == None:
return None

current = self.head
while current:
if current.value > max:
max= current.value
current = current.next

return max



# method to delete the first node found with specified value
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def delete(self, value):
pass
current = self.head
previous = None
if not current:
return None
if current.value == value:
self.head = current.next
return
while current:
if current.value == value:
previous.next = current.next
return
previous = current
current = current.next

# method to print all the values in the linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(n)
def visit(self):
helper_list = []
current = self.head
Expand All @@ -86,17 +154,33 @@ def visit(self):

# method to reverse the singly linked list
# note: the nodes should be moved and not just the values in the nodes
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def reverse(self):
pass
if not self.head:
return None
else:
current =self.head
previous = None
next = None
while current:
next = current.next
current.next = previous
previous = current
current = next
self.head = previous

## Advanced/ Exercises
# returns the value at the middle element in the singly linked list
# Time Complexity: ?
# Space Complexity: ?
# Time Complexity: O(n)
# Space Complexity: O(1)
def find_middle_value(self):
pass
before = self.head
after = self.head
while after and after.next:
after = after.next.next
before = before.next
return before.value

# find the nth node from the end and return its value
# assume indexing starts at 0 while counting to n
Expand Down