Pine - Alma and Ainur #62
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Co-authored-by: abecerrilsalas <[email protected]>
…value of the square is empty it changes it to 'X', otherwise to 'o'
CheezItMan
reviewed
Dec 23, 2021
| The file `package.json` contains details about our project, the scripts available, and the dependencies needed. We can inspect this file when we are curious about the details of our dependencies. | ||
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| 6. Follow the directions in the "Getting Started" section. | ||
| 6. Follow the directions in the "Getting Started" section.w |
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Suggested change
| 6. Follow the directions in the "Getting Started" section.w | |
| 6. Follow the directions in the "Getting Started" section. |
| const [currentSquare, setCurrentSquare] = useState(false); | ||
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| // Wave 2 | ||
| const changeTheSquare = (id) => { |
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👍 Nice work, very straightforward solution.
| // When it is clicked on. | ||
| // Then pass it into the squares as a callback | ||
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| const checkForWinner = () => { |
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This looks like it works to detect a winner. The only problem is that you're using 'X' instead of 'x' etc
| let countX = 0; | ||
| let countO = 0; | ||
| for (let col = 0; col < 3; col += 1) { | ||
| if (squares[row][col] === 'X') { |
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This kind of change should be made throughout the function.
Suggested change
| if (squares[row][col] === 'X') { | |
| if (squares[row][col].value === PLAYER_1) { |
| } | ||
| } | ||
| //Check dioganals | ||
| if (squares[0][0] == 'X' && squares[1][1] == 'X' && squares[2][2] == 'X') { |
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Watch the == use === instead
Suggested change
| if (squares[0][0] == 'X' && squares[1][1] == 'X' && squares[2][2] == 'X') { | |
| if (squares[0][0].value === PLAYER_1 && squares[1][1].value === PLAYER_1 && squares[2][2].value === PLAYER_1) { |
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