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5 changes: 4 additions & 1 deletion CONTRIBUTORS.md
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<h1>✨Happy Hacktoberfest 2023✨</h1>
<p>Hacktoberfest is a yearly event which encourages not only programmers and coders but also non-technical background to contribute in open source and start their journey with open source.</p>
<h1>Star Repo is Mandatory for Hactober Accepting!</h1>
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| Ankita Sinha Ray |<a href="https://github.com/ankitasray">ankitasray</a>|
| Aditya Pandey |<a href="https://github.com/Aditya7pandey">Aditya7pandey</a>|
| Yash Bandal |<a href="https://github.com/Yash-Bandal">Yash Bandal</a>|
| Harshit Jaiswal |<a href="https://github.com/harshu84190">Harshit Jaiswal</a>|
| Harshit Jaiswal |<a href="https://github.com/harshu84190">Harshit Jaiswal</a>|
| Yashal Ali |<a href="(https://github.com/yashal-ali)">Yashal Ali </a>|

31 changes: 31 additions & 0 deletions Python/mergeTwoSortedList.py
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# Merge Two Sorted Lists
# You are given the heads of two sorted linked lists list1 and list2.
# Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
# Return the head of the merged linked list.

# Input: list1 = [1,2,4], list2 = [1,3,4]
# Output: [1,1,2,3,4,4]

class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next

class Solution:
def mergeTwoLists(self, list1, list2):
curr = dummy = ListNode()
while list1 and list2:
if list1.val < list2.val:
curr.next = list1
list1 = list1.next
else:
curr.next = list2
list2 = list2.next
curr = curr.next

if list1:
curr.next = list1
else:
curr.next = list2

return dummy.next