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50 changes: 50 additions & 0 deletions minyoung/week8/달팽이문제.c
Original file line number Diff line number Diff line change
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#include <stdio.h>
#include <stdlib.h>
int dir;


int* solution(int n) {
int size = n * (n + 1) / 2;
int* answer = (int*)malloc(sizeof(int) * size);

// 배열 저장할 곳(2차원 매트릭스) 생성
int** arr = (int**)malloc(sizeof(int*) * n);
for (int i = 0; i < n; i++) {
arr[i] = (int*)calloc(i + 1, sizeof(int));
}

int row = -1, col = 0;
int num = 1;

// 로직 진행
for (int step = n; step > 0; step--) {
// 방향 세팅
dir = (n - step) % 3;

for (int i = 0; i < step; i++) {
if (dir == 0) { // 아래로
row++;
} else if (dir == 1) { // 오른쪽
col++;
} else { // 좌상향
row--;
col--;
}
arr[row][col] = num++;
}
}

int idx = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j <= i; j++) {
answer[idx++] = arr[i][j];
}
}

for (int i = 0; i < n; i++) {
free(arr[i]);
}
free(arr);

return answer;
}
47 changes: 47 additions & 0 deletions minyoung/week8/하노이.c
Original file line number Diff line number Diff line change
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#include <stdio.h>
#include <stdlib.h>

int **answer;
int idx = 0;

// 옮길 원반 갯수
// from 원래 원반들이 있는 곳
// via 일단 옮겨 두는 곳
// to 옮길 목적지
void hanoi(int n, int from, int via, int to) {
if (n == 1) {
answer[idx][0] = from;
answer[idx][1] = to;
idx++;
return;
}

hanoi(n - 1, from, to, via); // 위에 있는 n-1개 이동
hanoi(1, from, via, to); // 가장 큰 원판 이동
hanoi(n - 1, via, from, to); // 다시 n-1개 이동
}

int** solution(int n, int* returnSize, int** returnColumnSizes) {
// 2^n - 1 계산 -> 원반 이동할 총 횟수 알기 위해
int total = 1;
for (int i = 0; i < n; i++) {
total *= 2;
}
total -= 1;

// 이동경로 저장할 곳 생성
answer = (int**)malloc(sizeof(int*) * total);
*returnColumnSizes = (int*)malloc(sizeof(int) * total);

for (int i = 0; i < total; i++) {
answer[i] = (int*)malloc(sizeof(int) * 2);
(*returnColumnSizes)[i] = 2;
}

idx = 0;
hanoi(n, 1, 2, 3);

*returnSize = total;
return answer;
}