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fix interpolation: get floor of row and col index #1

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fix interpolation: get floor of row and col index #1

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5 changes: 3 additions & 2 deletions contrast.py
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Original file line number Diff line number Diff line change
@@ -1,5 +1,6 @@
#-*- coding:utf-8 -*-

import math
from PIL import Image, ImageOps
import numpy as np
from matplotlib import pyplot as plt
Expand Down Expand Up @@ -160,8 +161,8 @@ def contrast_limited_ahe(self, img_arr, level = 256, blocks = 8, threshold = 10.
arr = img_arr.copy()
for i in range(m):
for j in range(n):
r = int((i - block_m / 2) / block_m) # the row index of the left-up mapping function
c = int((j - block_n / 2) / block_n) # the col index of the left-up mapping function
r = int(math.floor((i - block_m / 2) / block_m)) # the row index of the left-up mapping function
c = int(math.floor((j - block_n / 2) / block_n)) # the col index of the left-up mapping function

x1 = (i - (r + 0.5) * block_m) / block_m # the x-axis distance to the left-up mapping center
y1 = (j - (c + 0.5) * block_n) / block_n # the y-axis distance to the left-up mapping center
Expand Down