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variance
Subhajit Sahu edited this page Aug 9, 2022
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1 revision
Find the mean of squared deviation of bigints from its mean.
function variance(...xs)
// xs: a list of bigints
const xbigint = require('extra-bigint');
xbigint.variance(1n, 2n);
// → 0n
xbigint.variance(1n, 2n, 3n);
// → 0n
xbigint.variance(1n, 2n, 3n, 4n);
// → 1n