DocBook-DTD: Match full docbook DTD as well as simplified - #3008
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Can you link the source code or the license that uses this variant? |
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I couldn't find an authorative git archive for a direct link, but it's in this archive: http://www.oasis-open.org/docbook/sgml/4.1/docbk41.zip in the And copied here for reference: <!-- Copyright 1992-2000 HaL Computer Systems, Inc.,
O'Reilly & Associates, Inc., ArborText, Inc., Fujitsu Software
Corporation, and the Organization for the Advancement of
Structured Information Standards (OASIS).
$Id: docbook.dtd,v 1.11 2000/06/19 14:42:02 nwalsh Exp $
Permission to use, copy, modify and distribute the DocBook DTD and
its accompanying documentation for any purpose and without fee is
hereby granted in perpetuity, provided that the above copyright
notice and this paragraph appear in all copies. The copyright
holders make no representation about the suitability of the DTD for
any purpose. It is provided "as is" without expressed or implied
warranty.
If you modify the DocBook DTD in any way, except for declaring and
referencing additional sets of general entities and declaring
additional notations, label your DTD as a variant of DocBook. See
the maintenance documentation for more information.
Please direct all questions, bug reports, or suggestions for
changes to the docbook@lists.oasis-open.org mailing list. For more
information, see http://www.oasis-open.org/docbook/.
--> |
Author
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Looks like I missed another minor difference, let me fix that... |
Makes the work "Simplified" optional in the Docbook DTD license so that it will match both the full Docbook DTD license and the Simplified Docbook DTD license. Signed-off-by: Joshua Watt <JPEWhacker@gmail.com>
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Makes the work "Simplified" optional in the Docbook DTD license so that it will match both the full Docbook DTD license and the Simplified Docbook DTD license.